3x^2/3-17x^1/3-6=0

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Solution for 3x^2/3-17x^1/3-6=0 equation: 


x in (-oo:+oo)

(3*x^2)/3-((17*x^1)/3)-6 = 0

(3*x^2)/3+(-17/3)*x-6 = 0

x^2-17/3*x-6 = 0

DELTA = (-17/3)^2-(-6*1*4)

DELTA = 505/9

DELTA > 0

x = ((505/9)^(1/2)+17/3)/(1*2) or x = (17/3-(505/9)^(1/2))/(1*2)

x = ((505/9)^(1/2)+17/3)/2 or x = (17/3-(505/9)^(1/2))/2

x in { (17/3-(505/9)^(1/2))/2, ((505/9)^(1/2)+17/3)/2 }

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